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kumpel [21]
3 years ago
9

How many solutions does this equation have?

Mathematics
2 answers:
user100 [1]3 years ago
6 0
One solution

Hgyugyhvd
Pavel [41]3 years ago
4 0

Answer:

one solution..........

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Help with translations!
Vadim26 [7]

Given:

The figure of a trapezoid.

The figure is translated down 5 units and then rotated 180 degrees clockwise.

To find:

The coordinates of the image of point W after these transformation.

Solution:

From the given figure it is clear that the coordinates of point W are (-6,3).

The figure is translated down 5 units. So,

(x,y)\to (x,y-5)

W(-6,3)\to W'(-6,3-5)

W(-6,3)\to W'(-6,-2)

After that the figure is rotated 180 degrees clockwise.

(x,y)\to (-x,-y)

W'(-6,-2)\to W''(6,2)

Therefore, the coordinates of point W after the given transformations are (6,2).

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3 years ago
Jonah wants to construct a confidence interval using 90% confidence to estimate what proportion of silicon wafers at his factory
Nimfa-mama [501]

Answer:

170

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Assume:

\pi = 0.06

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

What is the smallest sample size required to obtain the desired margin of error?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.06*0.94}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.06*0.94}

\sqrt{n} = \frac{1.645\sqrt{0.06*0.94}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.06*0.94}}{0.03})^2

n = 169.6

Rounding up, 170.

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