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3 years ago

Rewrite the expression using distributive property : 30x + 6

Mathematics

1 answer:

Anit [1.1K]3 years ago

6 0

Answer:

This cannot be done, but it can be factored as: 6(5x + 1)

Step-by-step explanation:

This expression cannot be distributed any further.

The distributive property is used when multiplying polynomials (multiplying one or more terms by two or more terms). In which case, each term in multiplied by each of the terms in the bracket, for example: .

5(x + 2) = 5x + 10

We can factor this expression however to go the opposite direction:

30x + 6

Since 30 and 6 are both divisible by 6, we can factor it out of each term.

Divide 30x by 6 and divide 6 by 6.

6(5x + 1)

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A square has a side length of 6x+2. a rectangle with width 3x+1 has the same area as the square. what is the length of the recta

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Answer:

Step-by-step explanation:

(6x+2)/(3x+1) = 2

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3 years ago

The diagonal of the rectangle is 10 inches long and the height of the rectangle is 8 inches. What is the perimeter of the rectan

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Basic perimeter is really easy to understand;

Step-by-step explanation:

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2 years ago

Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

3 years ago

-5-3 what does it equal

Leni [432]

-8 is the answer to your question

6 0

3 years ago

Read 2 more answers

A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun

bija089 [108]

Answer:

$3x^{3}+15x^{2}+x+5$

Step-by-step explanation:

We are told that the area of the bag can be represented by the function $f(x)=3x^{2} +1$ and as the bag is raised up its height can be represented by the function $g(x)=x +5$ .

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.

$\text{Volume of collapsible bag}=f(x)*g(x)$

$\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)$

After using distributive property we will get,

$\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)$

$\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5$

Therefore, the collapsible bag can hold $3x^{3}+15x^{2}+x+5$ grain.

6 0

3 years ago