The answer is 0.73 hope it helps
x - y = 16
x^2 + x^2 = 130
----------------
x^2 - y^2 = 256
+(x^2 + y^2 = 130)
2x^2 = 386
x^2 = 193
x = <span>13.892 (3DP)
----
</span>x - y = 16
13.892 - y = 16
-y = 2.108
y = -2.108
The numbers are: 13.892 and -2.108
First Question:
Number of trapezoids - 6
Perimeter - 72
3 + 3 + 3 + 6 = <u>15</u>
3 + 3 + 3 + 3 + 6 + 6 = <u>24</u>
3 + 3 + 6 + 3 + 3 + 6 + 3 + 6 = <u>33</u>
15 + 24 + 33 = <u>72</u>
Second Question:
Number of cubes - 6
Surface area - 24 (probably 480 since it said <em>area</em>)
first cube - 6 ones
second cube - 8 ones
Third cube - 10 ones
you could do 6 + 8 + 10 = 24 or add up all the ones (1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1) and you will still get 24
(It said <em>area</em>, and area means to multiply so maybe its 6 x 8 x 10 = 480 and not 6 + 8 + 10)
Anyways have a good day/night :) I might be wrong, but I hope I helped at least a little
Answer:
The cost of 2 quintal of rice is $10,000.
Step-by-step explanation:
To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.
Now, to determine the cost per kilogram of rice, the following calculation is required:
4,500 / 90 = X
50 = X
Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.
Answer:
33x-25
Step-by-step explanation:
2(3x-5)-3(6-4x)+(15x+3)
6x-10-18+12x+15x+3
21x+12x-10-18+3
=33x-25
