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Ahat [919]
3 years ago
7

-6 = 2x i need helppppp plzzzzz

Mathematics
2 answers:
dybincka [34]3 years ago
8 0

Answer:

x= negative 3

Step-by-step explanation:

-6 divided by 2 is -3

Flura [38]3 years ago
8 0

Isolate the variable by dividing each side by factors that don't contain the variable.

x = −3

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The vertices of a triangle are A(4, 1), B(9, 1), C(2, 5). What is the area of this triangle.
kiruha [24]

Hey there!

\large\boxed{10u^2}

Formula for the area of a triangle is (1/2)bh.

Base of this triangle is 5, height is 4.

Image attached.

Plug values into the formula:

A = (1/2)(5)(4)

Simplify.

A = (1/2)(20)

A = 10

Area of the triangle is 10 units².

Hope this helps!

6 0
3 years ago
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The lock on a safe requires a three-digit code to open it. The three digits must each be a number from 0-9 (10 possible numbers)
vovangra [49]
The correct answer is Choice B: 720.

To solve this, you have to use the Fundamental Counting Principal. You find the total number of options for each of the digits, then multiply them together.

For the first one, there are 10 options, then 9 options and finally 8 options.

10 x 9 x 8 = 720
7 0
3 years ago
Help me ASAP PLEASE
lina2011 [118]

Answer:

  4. Functions: 1, 2, 4, 5, 7, 8, 11, 12

  5. y = -1/2x+5/2, x ≤ -1; 2x +1, x > -1.

      y = 2, x < 0; x, 0 ≤ x ≤ 3; 3 x > 3.

Step-by-step explanation:

4. A list of ordered pairs is a function of no x-values are re-used. In (3) and (6), the value x=2 is used more than once.

A graph represents a function if it passes the "vertical line test." A vertical line cannot intersect the graph in 2 or more points. (9) and (10) both fail that test.

If the relation is not listed here as being "not a function," then it is one of the answers to question 4.

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5. The first step in writing the equation of a piecewise function is to identify the pieces. These are generally bounded by points of discontinuity--jumps in the function value, or changes in the slope of lines.

The second step is to identify the section of the function that boundary points belong to. Solid dots are part of the function definition; open circles are not.

<u>Left Graph</u>

The left piece ends at x=-1. There is a solid dot attached to the left piece, so its definition will be for the domain x ≤ -1. That line has slope -1/2, since is drops 1 unit for each 2 to the right. If extended, it would intersect the y-axis at y = 2 1/2 = 5/2. So, the piece on the left is y = -1/2x + 5/2 for x ≤ -1.

The right piece starts at x=-1, but does not include that point. It has a rise of 2 for each 1 to the right, so its slope is 2. It crosses the y-axis at y=1, so the piece on the right is y = 2x + 1 for x > -1.

You can use the method of your textbook author to combine theses pieces into one equation. The method shown above is one way to do it.

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<u>Right Graph</u>

This graph has a discontinuity at x=0 and a change in slope at x=3. It can be described by 3 pieces. The point at x=0 does not belong to the left piece, but goes with the middle piece.

The left piece of the function is the constant 2, so has the equation y = 2 for x < 0.

The middle piece has a slope of 1 and a y-intercept of 0, so has the equation y = x for 0 ≤ x ≤ 3.

The point at x=3 belongs to both the middle piece and the right piece, so can be part of both function definitions, if you like. Generally, it is better form to include any given x-value in only one of the pieces of the function. So the equation for the right piece can be y = 3 for x > 3.

4 0
3 years ago
Can some answer pls.
kirill [66]

Answer:

E. (7,-2)

Step-by-step explanation:

5 0
3 years ago
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Two certificates of deposit pay interest that differ by 3%. Money invested for one year in the first CD earns $240 interest. The
Soloha48 [4]

a = interest rate of first CD

b = interest rate of second CD

and again, let's say the principal invested in each is $X.

\bf a-b=3\qquad \implies \qquad \boxed{b}=3+a~\hfill \begin{cases} \left( \frac{a}{100} \right)X=240\\\\ \left( \frac{b}{100} \right)X=360 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \left( \cfrac{a}{100} \right)X=240\implies X=\cfrac{240}{~~\frac{a}{100}~~}\implies X=\cfrac{24000}{a} \\\\\\ \left( \cfrac{b}{100} \right)X=360\implies X=\cfrac{360}{~~\frac{b}{100}~~}\implies X=\cfrac{36000}{b} \\\\[-0.35em] ~\dotfill\\\\

\bf X=X\qquad thus\qquad \implies \cfrac{24000}{a}=\cfrac{36000}{b}\implies \cfrac{24000}{a}=\cfrac{36000}{\boxed{3+a}} \\\\\\ (3+a)24000=36000a\implies \cfrac{3+a}{a}=\cfrac{36000}{24000}\implies \cfrac{3-a}{a}=\cfrac{3}{2} \\\\\\ 6-2a=3a\implies 6=5a\implies \cfrac{6}{5}=a\implies 1\frac{1}{5}=a\implies \blacktriangleright 1.2 = x\blacktriangleleft

\bf \stackrel{\textit{since we know that}}{b=3+a}\implies b=3+\cfrac{6}{5}\implies b=\cfrac{21}{5}\implies b=4\frac{1}{5}\implies \blacktriangleright b=4.2 \blacktriangleleft

3 0
3 years ago
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