I’ll assume the c is b. (1/2) x (5) x (2) x (2) is 10
The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m
<h3>How to find the dimensions of the rectangle?</h3>
For a rectangle of length L and width W, the diagonal is:

Here we know that the diagonal is 169m.
And the ratio of the length to the width is 12:5
This means that:
W = (5/12)*L
Replacing all that in the diagonal equation:

So the length is 156 meters, and the width is:
W = (5/12)*156 m = 65m
Finally, the perimeter is:
P = 2*(L + W) = 2*(156 m + 65m) = 442m
If you want to learn more about rectangles:
brainly.com/question/17297081
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Answer:
18
Step-by-step explanation:
21-n; n=3
Substitute n for 3:
Solve.
The square is 130 in squared and the other shape is 54 in squared. If you're looking for the sum of the whole thing, its 185 in squared.
square: 13*10=130
triangle: 7*4= 28/2=14
rectangle: 10*4=40