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Gekata [30.6K]
2 years ago
14

Find the indicated real \large nth root(s) of \large a. \large n=6, \large a=64

Mathematics
1 answer:
pogonyaev2 years ago
7 0

Answer:

e

Step-by-step explanation:

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3+g=- 134

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What is the solution x+2y=7 and x-2y=-1
erica [24]

\underline{+\left\{\begin{array}{ccc}x+2y=7\\x-2y=-1\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad\qquad2x=6\qquad\text{divide both sides by 2}\\.\qquad\qquad \boxed{x=3}\\\\\text{Put the value of x to the first equation}\\\\3+2y=7\qquad\text{subtract 3 from both sides}\\\\2y=4\qquad\text{divide both sides by 2}\\\\\boxed{y=2}\\\\Answer:\ \boxed{x=3\ and\ y=2\to(3,\ 2)}

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2 years ago
Wright 6.789 in word form
max2010maxim [7]
Six point seven hundred eighty-nine thousandths.

3 0
3 years ago
Read 2 more answers
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
3 years ago
Read 2 more answers
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