<h3><u>Answer:</u></h3>

<h3><u>Solution</u><u>:</u></h3>
we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

Here,
- hypotenuse = 23 feet
= 76°- Value of Sin
= 0.97 - Perpendicular = ?





ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

This is an arithmetic sequence because each term is 7 greater than the previous term, so 7 is what is called the common difference...
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=first term, d=common difference, n=term number.
We know a=1 and d=7 so:
a(n)=1+7(n-1)
a(n)=1+7n-7
a(n)=7n-6
The above is the "rule" for the nth term.
P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
</span>
<span>P(t) = P(0)[exp(-0.0202t)]</span>