Answer:
y=69
Step-by-step explanation:
first step:when y=26 and x=21
c=y-x
c=26-21
c=5
second step: when y is unknown and x=64
To find y we simply add the value of c to x
y=x+c
y=64+5
y=69
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)
a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.
A(0,0,0)
Reflecting
A(0,0,0)
B(0,5,0)
Reflecting
B(0,-5,0)
C(3,5,0)
Reflecting
C(3,-5,0)
D(3,0,0)
Reflecting
D(3,0,0)
b.)
A(0,0,0)
Moving
A(-2,-3,1)
B(0,-5,0)
Moving
B(-2,-8,1)
C(3,-5,0)
Moving
C(1,-8,1)
D(3,0,0)
Moving
D(1,-3,1)
Answer:
2x, (x-2), (x+6)
Step-by-step explanation:
I just took the quiz on plato and I got it correct
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Answer:
Part A:
(1) x + y = 95
(2) x = y + 25
Part B:
The number of minutes Eric spends playing volleyball each day is 35 minutes
Part C:
It is not possible for Eric to have spent exactly 35 minutes playing basketball
Step-by-step explanation:
The total time Eric plays basketball and volleyball = 95 minutes
The time duration Eric plays basket ball = x
The time duration Eric plays volleyball = y
Part A:
The pair of relationships between the number of minutes Eric plays basketball (x) and the number of minutes he plays volleyball (y) are;
(1) x + y = 95
(2) x = y + 25
Part B:
By substituting the value of x in equation (2) into equation (1), we have;
x + y = (y + 25) + y = 95
2·y + 25 = 95
2·y = 95 - 25 = 70
y = 70/2 = 35 minutes
Therefore, Eric spends 35 minutes playing volleyball every day
Part C:
It is not possible for Eric to have spent only 35 minutes playing basketball because, given that he plays basketball for 25 minutes longer than he plays volley, the number of minutes he spends playing volleyball will then be given as follows;
x = y + 25
35 = y + 25
y = 35 - 25 = 10 minutes
The total time = x + y = 10 + 35 = 45 minutes ≠ 95 minutes.