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3 years ago

Pls help. I WILL MARK BRAINLIEST!

Mathematics

2 answers:

goblinko [34]3 years ago

6 0

Answer:

Step-by-step explanation:

because if you look at the line below it it shows 180 degrees because it is a straight line if that makes sense. if not just trust me.

Over [174]3 years ago

5 0

Im sorry- everyone is saying its C so- Uh... sorry :<

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Solve using the quadratic formula. Approximate answers to the nearest tenth.

Thepotemich [5.8K]

Answer:

$\displaystyle x = 2, \ 3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

Step 1: Define

Identify variables

x² - 5x + 6

↓

a = 1, b = -5, c = 6

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x = \frac{5 \pm \sqrt{(-5)^2-4(1)(6)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x = \frac{5 \pm \sqrt{25-4(1)(6)}}{2(1)}$
[√Radical] Multiply: $\displaystyle x = \frac{5 \pm \sqrt{25-24}}{2(1)}$
[√Radical] Subtract: $\displaystyle x = \frac{5 \pm \sqrt{1}}{2(1)}$
[√Radical] Evaluate: $\displaystyle x = \frac{5 \pm 1}{2(1)}$
Multiply: $\displaystyle x = \frac{5 \pm 1}{2}$
Add/Subtract: $\displaystyle x = \frac{4}{2}, \ \frac{6}{2}$
Divide: $\displaystyle x = 2, \ 3$

6 0

3 years ago

Stefon is paid $25 to mow a lawn. This amount is $4 less than twice the amount he received when he first began mowing. Use the m

Neko [114]

Answer:

He used to receive $14.50.

Step-by-step explanation:

Let x = amount he used to receive.

Now he receives 2x - 4.

Now he receives $25.

2x - 4 = 25

2x = 29

x = 14.5

Answer: He used to receive $14.50.

5 0

2 years ago

Read 2 more answers

Find the zeros in the function 3x2+ 6 = 0

sattari [20]

Answer:

x = ± i $\sqrt{2}$

Step-by-step explanation:

Given

3x² + 6 = 0 ( subtract 6 from both sides )

3x² = - 6 ( divide both sides by 3 )

x² = - 2 ( take the square root of both sides )

x = ± $\sqrt{-2}$

= ± $\sqrt{2(-1)}$

= ± ( $\sqrt{2}$ × $\sqrt{-1}$ ) → $\sqrt{-1}$ = i

= ± i $\sqrt{2}$

5 0

4 years ago

Solve for x !! Help !!

zheka24 [161]

Answer:

Step-by-step explanation:

2x-9+x-2=16

3x-11=16

3x=27

x=9

7 0

3 years ago

Read 2 more answers

Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx

Rudiy27

If we use the substitution $u = \tan x$ , then $du = \sec^2 {x}\ dx$ . If you try substituting just $u$ and $du$ into the integrand, though, you'll notice that there's a $\sec^2x$ left over that we have to deal with.

To get rid of this problem, use the identity $\tan^2 x + 1 = \sec^2 x$ and substitute in the left side of the identity for the extra $\sec^2x$ , as shown:

$\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx$
$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$

From there, we can substitute in $u$ and $du$ , and then evaluate:

$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du$
$= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}$
$= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})$
$= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}$

8 0

3 years ago