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abruzzese [7]
2 years ago
15

How many parameters can we use in each function?

Computers and Technology
1 answer:
kari74 [83]2 years ago
8 0

Answer:

As many as we need

Explanation:

https://quizizz.com/admin/quiz/5e68ffb7ada381001bd58b3a/codehs-unit-2-lessons-13-to-19

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I. Given the following Java code fragment, what is output? int a, b; String c, d, e; String x = new String("I LOVE"); String y =
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Answer:

Output: The question segment gives the following output--

1) 6

2) 5

3) JAVA!  

4) i love

5) I LOVEjava!

Explanation:

  1. "1) 6" comes because "6" is the length of "I LOVE" which is the value of "x" variable and "x.length( )" statement gives the length of the value of "x" variable which is stored on "a" variable and "a" will be printed with "1)" symbol.
  2. "2) 5" comes because "5" is the length of "java!" which is the value of "y" variable and "y.length( )" statement gives the length of the value of "y" variable which is stored on "b" variable and "b" will be printed with "2)" symbol.
  3. "3) JAVA! " comes because "JAVA!" is the upper case letter of "java!" which is the value of "y" variable and "y.toUpperCase( )" statement change the value from lower case to uppercase of the value of "y" variable which is stored on "c" variable and "c" will be printed with "3)" symbol.
  4. "4) i love " comes because "i love" is the lower case letter of "I LOVE" which is the value of "x" variable and "x.toLowerCase( )" statement change the value from uppercase to lowercase of the value of "x" variable which is stored on "d" variable and "d" will be printed with "4)" symbol.
  5. "5) I LOVEjava! " comes because " I LOVEjava! " is the mixed value of the "x" and "y" variable. It prints because "x.concat(y);" statement combines the x and y value and stored in an "e" variable and "e" will be printed with "5)" symbol.
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Debugging is not testing, but always occurs as a consequence of testing. <br> A) TRUE<br> B) FALSE
kherson [118]
A) True Hope that helps
5 0
3 years ago
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