Answer:
Ss × ss
Explanation:
This question involves a single gene coding for hair length in guinea pigs. The alleles for short hair (S) is dominant over that of long hair (s).
According to this question, a guinea pig with short hair (S_) is crossed to one that has long hair (ss) to produce offsprings that have 44 short hair and 46 long hair. This number of offsprings produced indicate a ratio of 1:1, which can only be produced if the short haired guinea pig is heterozygous i.e. Ss.
Therefore, the genotype of the parents are Ss (short hair) and ss (long hair) i.e. Ss × ss. This combination will produce offsprings with the following proportion: Ss (1) : ss (1).
Each bone has a humerus. The ones that have these bones are humans, lions and birds
Answer:
The answer is double replacement :)
Answer:
<em>Electroencephalography.</em>
<em></em>
Explanation:
Electroencephalography is used to measure brain activity in terms of electrical activity. It is done by attaching electrodes on the scalp, or sometimes by placing electrodes directly in the brain. Using electroencephalography can help determine when the fetus starts having its own brain activities, which means that it is now a separate entity distinguishable from its mother. Using electroencephalography to see brain waves can give us a deeper insight into the age old complicated issue of when a mother and her conceptus become separate individuals.
