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umka2103 [35]
3 years ago
15

What's the value of x ​

Mathematics
1 answer:
schepotkina [342]3 years ago
5 0
Answer: x=14

Explanation: the angle needs to equal the other angle, which is 63. To figure this out, we subtract 21 from 63. We get 42. 42 divided by 3 is 14. We are basically doing the equation in reverse.
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Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?
Alborosie

Answer:

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

<u>Step 1:  Factor</u>

p(x) = x^3 - 5x^2 - x + 5

<em>p(x) = (x - 5)(x + 1)(x - 1)</em>

<em />

<em>Yes, the remainder is 0 so, x-5 is a factor of p(x)</em>

<em />

Answer:  Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

8 0
3 years ago
A chef planning for a large banquet thinks that 2 out of every 5 dinner guests will order soup. 800 guests are going to be at th
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Answer:

The Chef will prepare 320 soups for a large banquet

Step-by-step explanation:

chef thinks that 2 out of every 5 dinner guests will order soup

===> Order soup / total number of attender

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2 /5 = x /800

cross multiplying

x = 2 x 800 / 5

= 320

The Chef will prepare 320 soups for a large banquet

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4 years ago
On December 13, 2007, one British pound was worth 2.04 U.S. dollars.
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Answer:

a) 5 pounds

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A cigarette industry spokesperson remarks that current levels of tar are no more than 5 milligrams per cigarette. A reporter doe
d1i1m1o1n [39]

Answer:

t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516  

df=n-1=15-1=14  

Since is a right tailed test the p value would be:  

p_v =P(t_{14}>1.516)=0.076  

If we use a significance level of 0.05 we see that p_v > \alpha and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

Step-by-step explanation:

Data given and notation  

\bar X=5.63 represent the sample mean  

s=1.61 represent the standard deviation for the sample  

n=15 sample size  

\mu_o =15/tex] represent the value that we want to test  &#10;[tex]\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the average is more than 5.63, the system of hypothesis would be:  

Null hypothesis:\mu \leq 5.63  

Alternative hypothesis:\mu > 5.63  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516  

Now we need to find the degrees of freedom for the t distribution given by:

df=n-1=15-1=14  

P value

Since is a right tailed test the p value would be:  

p_v =P(t_{14}>1.516)=0.076  

If we use a significance level of 0.05 we see that p_v > \alpha and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

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Virty [35]

Answer:

It would be rounded to $5.90 per gallon. As if something is 5 or above you round up and if it is 4 or less you round down.

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3 years ago
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