Answer: $3,166
Step-by-step explanation:
Dude, it's impossible to solve without the pic
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
Assume that the number is 100. Then, 20% of 100 is 20×100100 = 20. Increasing 100 by 20% means increasing 100 by 20 and the resultant number is 120.
The answer is 11.2
The Pythagorean Theorem says
a^2+b^2=c^2
From the picture, we know one side, and the hypotenuse.
10^2+b^2=15^2
100+b^2=225
b^2=225
Sqrtb^2=sqrt225
b=11.18
Rounded to the nearest tenth it is 11.2
