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krek1111 [17]
3 years ago
8

I am so stuck! :( Pls help me!!! I don't get the problem and I don't know how to solve it

Mathematics
2 answers:
stiks02 [169]3 years ago
8 0

Answer:

(n^2)/2a

Step-by-step explanation:

We'll take this in small steps. Don't worry and follow along if you wish :D

Where do we start? Well, first, we notice that all of the numbers/variables (on both the denominator and the numerator) are multiplied by each other. If this case had addition or subtraction in the fraction, the explanation would have differed.

Let's take on a simpler example to show you what I mean. Here's a relatively simpler equation with no pesky variables:

(1 + 3)/4

This equation has to be broken down like this:

1/4 + 3/4

And although we could just do (1 + 3) quickly and divide by 4, consider it if we replace them with numbers instead, or variables in other words:

(<em>x</em> + <em>y</em>)/<em>x</em>

Then, it would work the same way as the previous example:

<em>x</em>/<em>x</em> + <em>y</em>/<em>x</em>

And that would further simplify to (1 + <em>y</em>/<em>x</em>).

But, we're lucky! Because there is <em>no </em>addition or subtraction, we won't have to divide all the numbers that are in the numerator with the number(s) in the denominator. Consider this:

(3*4)/4

We only need to divide 4 by the denominator (which is also four, in this case) and not <em>both</em> 3 and 4 like how we would solve if it had addition or subtraction.

First step! Let's take all of the variables out of this nasty equation we have on our hands to make it simpler:

(9<em>an</em>^3)/(18<em>a^2n</em>)

We would be left with...

9/18

And then we would reduce to leave 1/2. Notice that if we add all the variables back, we would have:

(1<em>an^3</em>)/(2<em>a^2n</em>)

Or (<em>an^3</em>)/(2<em>a^2n</em>)

If we write it out, we'll find this equation a tad bit easier with the large numbers dealt with (although I will admit, it doesn't look that great on the screen—lol)!

Back to business. Here, we need to simplify the variables. Given, we have to remember that variables are just your every-day number (but unknown). Because of that, we get to divide them very much like how we would with regular numbers. Rope in some of our previous lesson about not having to divide <em>all </em>the numbers on the numerator from the denominator from the beginning, too!

(<em>an^3</em>)/(2<em>a^2n</em>)

You can cancel out the variable <em>a^</em> in this equation. That would leave you with:

(<em>n^3</em>)/(2<em>an</em>)

Try to simplify the rest on your own and use my work to check your answers! if you can't, then no worries. Follow along with me :D

We can also reduce using <em>n. </em>That will leave:

(<em>n^2</em>)/2<em>a</em>

And then you're done! I would recommend more questions like these (if you aren't already doing them) because you'll be using simplifying techniques similar to this equation in the future.

Good luck and keep studying!

Lelu [443]3 years ago
4 0

Answer:

\frac{n^{2}}{2a}

Step-by-step explanation:

  • Just split it up first \frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}
  • Then 9 divided by 18 can be simplified into the fraction 1/2
  • What can go into a and a^2 ? a itself right, so if you divide a by a you get 1, if you divide a^2 by a you get a
  • Same as the a fraction, if you divide n^3 by n you get n^2
  • \frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}=\frac{1}{2}\times \frac{1}{a} \times\frac{n^2}{1}=\frac{n^{2}}{2a}
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