Which is NOT supported by this graph?

Which of the following does not factor as a perfect square trinomial?

Ede4ka [16]

Answer:

Option C. x^2-18x-81

Step-by-step explanation:

A. 16a^2-72a+81

x^2-2xy+y^2=(x-y)^2

x^2=16a^2→sqrt(x^2)=sqrt(16a^2)→x=sqrt(16) sqrt(a^2)→x=4a

y^2=81→sqrt(y^2)=sqrt(81)→y=9

2xy=2(4a)(9)→2xy=72a equal to the second term of the expression, then we can factor as a perfect square trinomial:

16a^2-72a+81=(4a-9)^2

B. 169x^2+26xy+y^2

a^2+2ab+b^2=(a+b)^2

a^2=169x^2→sqrt(a^2)=sqrt(169x^2)→a=sqrt(169) sqrt(x^2)→a=13x

b^2=y^2→sqrt(b^2)=sqrt(y^2)→b=y

2ab=2(13x)(y)→2ab=26xy equal to the second term of the expression, then we can factor as a perfect square trinomial:

169x^2+26xy+y^2=(13x+y)^2

C. x^2-18x-81

a^2+2ab+b^2=(a+b)^2

This expression does not factor as a perfect square trinomial because the third term is negative (-81).

D. 4x^2+4x+1

a^2+2ab+b^2=(a+b)^2

a^2=4x^2→sqrt(a^2)=sqrt(4x^2)→a=sqrt(4) sqrt(x^2)→a=2x

b^2=1→sqrt(b^2)=sqrt(1)→b=1

2ab=2(2x)(1)→2ab=4x equal to the second term of the expression, then we can factor as a perfect square trinomial:

4x^2+4x+1=(2x+1)^2

4 0

3 years ago

What is the answer?

DochEvi [55]

Answer:

HL

Step-by-step explanation:

The hypotenuse and the "leg" are congruent...along with the 90 degree angle.

"The HL Postulate states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent." - Calcworkshop

4 0

3 years ago

Read 2 more answers

2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7 not pemdas

antiseptic1488 [7]

60

See steps

Step by Step Solution:

More Icon

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "2.7" was replaced by "(27/10)". 8 more similar replacement(s)

STEP

1

:

27

Simplify ——

10

Equation at the end of step

1

:

27 62 93 12 62 93 12 27

(((——•——)-(——•——))+(——•——))-(——•——)

10 10 10 10 10 10 10 10

STEP

2

:

6

Simplify —

5

Equation at the end of step

2

:

27 62 93 12 62 93 6 27

(((——•——)-(——•——))+(——•——))-(—•——)

10 10 10 10 10 10 5 10

STEP

3

:

93

Simplify ——

10

Equation at the end of step

3

:

27 62 93 12 62 93 81

(((——•——)-(——•——))+(——•——))-——

10 10 10 10 10 10 25

STEP

4

:

31

Simplify ——

5

Equation at the end of step

4

:

27 62 93 12 31 93 81

(((——•——)-(——•——))+(——•——))-——

10 10 10 10 5 10 25

STEP

5

:

6

Simplify —

5

Equation at the end of step

5

:

27 62 93 6 2883 81

(((——•——)-(——•—))+————)-——

10 10 10 5 50 25

STEP

6

:

93

Simplify ——

10

Equation at the end of step

6

:

27 62 93 6 2883 81

(((——•——)-(——•—))+————)-——

10 10 10 5 50 25

STEP

7

:

31

Simplify ——

5

Equation at the end of step

7

:

27 31 279 2883 81

(((—— • ——) - ———) + ————) - ——

10 5 25 50 25

STEP

8

:

27

Simplify ——

10

Equation at the end of step

8

:

27 31 279 2883 81

(((—— • ——) - ———) + ————) - ——

10 5 25 50 25

STEP

9

:

Calculating the Least Common Multiple

9.1 Find the Least Common Multiple

The left denominator is : 50

The right denominator is : 25

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

2 1 0 1

5 2 2 2

Product of all

Prime Factors 50 25 50

Least Common Multiple:

50

Calculating Multipliers :

9.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

9.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 837

—————————————————— = ———

L.C.M 50

R. Mult. • R. Num. 279 • 2

—————————————————— = ———————

L.C.M 50

Adding fractions that have a common denominator :

9.4 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

837 - (279 • 2) 279

——————————————— = ———

50 50

Equation at the end of step

9

:

279 2883 81

(——— + ————) - ——

50 50 25

STEP

10

:

Adding fractions which have a common denominator

10.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

279 + 2883 1581

—————————— = ————

50 25

Equation at the end of step

10

:

1581 81

———— - ——

25 25

STEP

11

:

Adding fractions which have a common denominator

11.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1581 - (81) 60

——————————— = ——

25 1

Final result :

60

7 0

3 years ago

The value of the cumulative standardized normal distribution at z is 0.8770. what is the value of z?

Vinvika [58]

The value of z is 0.8770. This answer was derived from information in the question, which states that the value of z is 0.8770. Granted, I don't understand what is meant by "cumulative standardized normal distribution." I only passed statistics because the professor felt sorry for me.

4 0

4 years ago

Read 2 more answers

The graph of a linear function passes through the points (-1, -1/4) and (1, -3/4). Which equation represents the function ?

lyudmila [28]

The equation of the line will be given as y = -4x - (- 17/ 4).

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given that:-

The graph of a linear function passes through the points (-1, -1/4) and (1, -3/4).

The equation of the line will be given as:-

y - y₁ = m ( x - x₁)

slope m will be calculated as:-

$m =\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1+1}{\dfrac{-3}{4}+\dfrac{1}{4}}=-4$

The equation will be:-

y - (1/4) = -4( x + 1 )

y = -4x - (17/4)

Therefore the equation of the line will be given as y = -4x - (- 17/ 4).

To know more about equations follow

brainly.com/question/2972832

#SPJ1

3 0

2 years ago