Question

Now, suppose one of the roots of the polynomial function is irrational. The roots of the function are 2, -dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}" align="absmiddle" class="latex-formula">, and 5. Write the equation for this polynomial function.
Which of the following must also be a root of the function?
A) -2
B) -$\sqrt{3}$
C) -5
D) $\sqrt{2}$

Answer 1

Irrational roots occurs with its conjugate.

Therefore, -√3 is also root of the function.

The answer is -√3.

Answer 2

answer:

b. -√3

hope this helps! :o)