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3 years ago

Last question and i can go!!! this is due today and im giving breainlies t !

Mathematics

2 answers:

olga55 [171]3 years ago

8 0

Answer:

Step-by-step explanation:

nataly862011 [7]3 years ago

6 0

Answer:

Hey There!

Here,

we've a circle with a radius =. 5(10/2)m

And a square with side =10m

The area of shaded region

➠ Area of Square- Area of Circle

➠10*10-(3.14*5*5)

➠100-78.5

➠21.5m² is the answer

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A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

4 0

3 years ago

How do you solve 1/2x<13?

Alisiya [41]

You need to get x alone on one side. You need to divide 1/2 on both sides which makes 13 a 26. x<26

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3 years ago

Help me yall this for me aint it.

aleksandrvk [35]

Answer:

20(4 + 5)

Step-by-step explanation:

GCF is just the biggest number each value can be divided by. Here, it's 20, so that goes outside of the parenthesis. Now, what can you multiply by 20 to get 80? 4, so that goes in the second box. What can you multiply by 20 to get 100? 5, so that goes in the last box. You can check your answer by doing 80 + 100 = 180; 20(9) = 180.

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The sequence an = one third(3)n − 1 is graphed below: coordinate plane showing the points 2, 1; 3, 3; and 4, 9 Find the average

Maru [420]

The given sequence is:

$a(n)= \frac{1}{3} (3)^{n-1}$

a(2)=1
a(3)=3
a(4)=9

We are to find the average rate of change between n=3 and n=4 for the given function.

Average rate of change = $\frac{a(4)-a(3)}{4-3} = \frac{9-3}{1}=6$

So the average rate of change for the given function from n = 3 to n = 4 is 6

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