1) 17, 29, 32, 9, 30, 14, 8, 39, 11, 32, 23<br>
Minimum :<br>
Maximum:<br>
Q1:<br>
Q2:<br>
Q3:
Lisa [10]
Answer:
Minimum: 8
Maximum: 39
Q1: 11
Q2: 23
Q3: 32
Step-by-step explanation:
Set the numbers into numerical order
8 9 11 14 17 23 29 30 32 32 39
Then separate into quarters
[8 9 11] [14 17 23] [29 30 32] 32 39
Step-by-step explanation:

Answer:
The answer is 30
Step-by-step explanation:
First you have to find 120% of a (12).

Therefore; 14.4 is 80% of b, and we are trying to find 100% of b

we do not know what is 100% therefore we call it *x*. In order to find this unknown value *x* we cross multiply.

This is the same as saying;

100% percent would be 1 because it is the whole number we are trying to find. The 80% would be 4/5. To get 4/5 you can simply break down 80/100 ( this is 80% as a fraction).
so the new equation is: 14.4= 4/5x
We divide both sides by 4/5. Then we will get x tobe equal to 18. Therefore b is 18. We were asked to find (a + b) so.<em> </em><em>1</em><em>8</em><em>+</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>30</em>
Answer:
a) 272 used at least one prescription medication.
b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).
Step-by-step explanation:
Question a:
86.6% out of 3149, so:
0.866*3149 = 2727.
272 used at least one prescription medication.
Question b:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
For this problem, we have that:
90% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
For the percentage:
0.856*100% = 85.6%
0.876*100% = 87.6%.
The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).
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