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3 years ago

Is this solved correctly ?

Mathematics

1 answer:

nadezda [96]3 years ago

7 0

Yes i believe so snnsndneneneme sna

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The lifetime of a machine part has a continuous distribution on the interval (0, 50) with probability density function f, whe

Strike441 [17]

Answer:

Probability that the lifetime of the machine part is less than 13 = 0.6782

Step-by-step explanation:

given that $f(x)=(10+x)^{-2}$

Normalizing the function we get

$\int_{0 }^{50}cf(x)dx=1$

$\int_{0 }^{50}c(10+x)^{-2}dx=1$

$\therefore a=\frac{1}{\int_{0 }^{50}(10+x)^{-2}dx}$

$\therefore a=12$

$P(x< 13)=\int_{0}^{13}12(10+x)^{-2}dx\\\\P(X< 13)=0.6782$

4 0

3 years ago

What is LaTeX: m\angle PQRm ∠ P Q R? Line PS with midpoint at Q and ray QR. Angle pqr is 3x-6 and angle rqs is x+2

Mkey [24]

Answer:

Step-by-step explanation:

If line PS has midpoint a Q and ray QR, then line PQS will be a straight line and <PQR + <RQS = 180 (sum of angle on a straight line).

Given

<PQR = 3x-6

<RQS = x+ 2

To get x, we will use the relationship above;

3x-6+x+2 = 180

4x-4 = 180

add 4 to both sides

4x-4+4 = 180+4

4x = 184

x = 184/4

x = 46

Since <PQR = 3x-6, we will substitute the value of x into the formula;

<PQR = 3x-6

<PQR = 3(46)-6

<PQR = 138-6

<PQR = 132°

Hence the size of angle PQR is 132°

6 0

3 years ago

A checkers board is eight squares long and eight squares wide. The area of each square is 14 cm². Estimate the perimeter of the

Tamiku [17]

Answer:

Perimeter of the board is 119.7 cm.

Step-by-step explanation:

We are given that,

Area of each square = 14 cm²

i.e. $Side^2=14$

i.e. $Side= \sqrt{14}$

i.e Side = 3.74 cm

So, we get the side of each square is 3.74 cm.

Since, Perimeter of a square = $4a$

→ Perimeter of each square = $4\times 3.74$

→ Perimeter of each square = 14.96 cm

<em>Since, there are 8×8= 64 squares on the board.</em>

Thus, the perimeter of the board = 8 × Perimeter of each square.

i.e. Perimeter of the board = 8 × 14.96

i.e. Perimeter of the board = 119.68 cm

Hence, the perimeter of the board rounded to the tenths is 119.7 cm.

4 0

3 years ago

Find the area of a triangle with a base of 25 inches and a hieght of 30 inches

svlad2 [7]

$A_{triangle}=\frac{1}{2}bh$
Where $b$ is the base
and $h$ is the height.

Just plug in the given values:

$A_{triangle}=\frac{1}{2}*25*30$
And solve for $A_{triangle}\\[tex]A_{triangle}=375in^{2}$

6 0

3 years ago

Easy fractions help please please thank you

guapka [62]

Answer:

1. B 2. B 3. A 4. A 5. A 6. B

Step-by-step explanation:

6 0

3 years ago

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