Question

Write the equation of a line perpendicular to the line: y=−5/2x+4 that goes through the point (-6, 0).

Answer 1

Step-by-step explanation:

the line given slope = x coefficient = -5/2

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

new slope = 2/5

line equation formula = y = mx+ b

m = slope

y= 2/5x + b

from the point given (-6,0)

x = -6

y = 0

0= -12/5 + b

b = +12/5

line equation =

$y = \frac{2}{5} x + \frac{12}{5}$