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charle [14.2K]
3 years ago
11

Write the set using the roster method A={a|a an even number and 15< a< =25}

Mathematics
1 answer:
pochemuha3 years ago
4 0

Answer:

{16, 17, 18, 19, 20, 21, 22,23, 24, 25}

Step-by-step explanation:

Given the set A={a|a an even number and 15< a< =25}

The inequality 15< a< =25 mean the set A consists of all the values between 15 and 25 with 25 inclusive (due to presence of the equal to sign)

Hence the required set A are {16, 17, 18, 19, 20, 21, 22,23, 24, 25}

Note that 15 is excluded from the set of number since 15<a i.e a > 15

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Two thirds times x plus 13 equals twenty two
Nataly [62]
2/3 * x +13 = 22
2/3x + 13 = 22 

 if u need to solve it then ....
=> 2/3x = 22 - 13
=> 2/3x = 9
=> 2x = 9*3 = 27
=> x = 27/2

Hope it helps !!!
6 0
3 years ago
If P is parentheses and M is Multiplication and S is subtraction, what is EDA In PEMDAS? Very confused!
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E is exponents, D is division, A is addition

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PART A: At the bakery, the daily ratio of cookie sales to donut sales is 4 to 3. Cookies and donuts cost the same amount. If the
BabaBlast [244]
Their ratio would be: Cookie / Donut = 4/3
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4 0
3 years ago
I need my smart homies to answer this question for me !
ella [17]

Answer:

Part A: chosen method is by factoring

Part B: First rewrite the equation by writing -24 as a difference so you get     x² -9x - 15x + 135 = 0. Then factor out the x and the -15 from the equation so you get x(x-9) - 15(x-9) = 0. Then factor out x-9 from the equation so you have (x-9)(x-15) = 0. Finally, set each expression to 0: x-9=0 and x-15=0 and then solve: x=9 and x=15

Part C: x=9, x=15

4 0
3 years ago
)) a. Write three side lengths that will
Zolol [24]

Answer:

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1,2 ,9 does not form a triangle

Step-by-step explanation:

Three side lengths that will form a triangle

3,4,5

This is a Pythagorean triple.  It forms a right triangle

3^2 +4^2 = 5^2

9+16=25

25=25

Three side lengths that will not form a triangle

1,2 9

The sum of the two smaller sides must be greater then the third

1+2 < 9 not greater

3 0
3 years ago
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