Using Newton-Raphsf (x) = 2x3 + x2 - x + 1 accurate to within 10-4
2 answers:
9514 1404 393
Answer:
-1.2338
Step-by-step explanation:
The graph shows the one real root is about -1.234. The Newton's method iterator is ...
new x = x - f(x)/f'(x) . . . . . where f'(x) is the derivative of f(x)
Many graphing calculators provide a derivative function, so the iteration equation can be evaluated more or less directly by the calculator. In the attached, we have shown a table with three iterations of the root. After the second iteration, the root is good to 4 decimal places.
x ≈ -1.2338
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