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Norma-Jean [14]
3 years ago
12

What is the solution to the following system of equations?

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0

Answer:B

Step-by-step explanation: no cap

Minchanka [31]3 years ago
5 0
<span>The correct answer is option B. i.e. (1,-10) two equations are y = -x^2 - 5x - 4 and y = -x^2 + 9x - 18. Now, equating both the equations we get, -x^2 - 5x - 4 = -x^2 + 9x - 18 or 14 x= 14 or x = 1. Now, y = -1 -5 -4 = -10.</span>
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Eva and Ola have some amount of money,
hram777 [196]

Answer:

<em>£</em><em>1</em><em>9</em>

Step-by-step explanation:

Cheryl = 7 + 5 = £12

this means ova and eva also have £12 at the end

EVA'S ORIGINAL AMOUNT : X -7 =12

X = £19

6 0
4 years ago
High school students from grades 9–10 and 11–12 were asked to choose the kind of band to have play at a school dance: rap, rock,
yanalaym [24]
The correct two-way frequency table for the date will look like this:
                 
                               RAP      ROCK     COUNTRY     TOTAL
Grades 9-10           40           30            55                  125
Grades 11-12         60           25            35                  120
TOTAL                    100          55            90                  245

The sum of the row total is equal to the sum of the column total
125 + 120 = 100 + 55 + 90
245 = 245
8 0
3 years ago
Read 2 more answers
Write a standard form of a quadratic equation that has roots - 5/2 and 3.
lora16 [44]

Answer:

2x^2 - x - 15 = 0.

Step-by-step explanation:

In factor form this is

(x + 5/2)(x - 3) = 0

x^2 + 5/2x - 3x  - 15/2 = 0

x^2 - 1/2x - 15/2 = 0

Multiply through by 2:

2x^2 - x - 15 = 0.

6 0
3 years ago
Please help!<br> 10<br> ∑ 2i-9<br> i=3
pentagon [3]

\sum\limits_{i=3}^{10}(2i-9)=2(3)-9+2(4)-9+2(5)-9+2(6)-9+2(7)-9\\\\+2(8)-9+2(9)-9+2(10)-9\\\\=6-9+8-9+10-9+12-9+14-9+16-9+18-9+20-9\\\\=90-72=18

6 0
3 years ago
The average cost of tuition plus room and board at small private liberal arts colleges is reported to be less than $18,500 per t
lys-0071 [83]

Answer:

The null and alternative hypothesis for this study are:

H_0: \mu=18500\\\\H_a:\mu< 18500

The null hypothesis is rejected (P-value=0.004).

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Then, the null and alternative hypothesis are:

H_0: \mu=18500\\\\H_a:\mu< 18500

The significance level is 0.05.

The sample has a size n=150.

The sample mean is M=18200.

The standard deviation of the population is known and has a value of σ=1400.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1400}{\sqrt{150}}=114.31

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{18200-18500}{114.31}=\dfrac{-300}{114.31}=-2.624

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

3 0
4 years ago
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