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ra1l [238]
3 years ago
10

Write the following equations in slope-intercept form.5x+y=30

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer:

y = -5x+30

Step-by-step explanation:

To write an equation in slope intercept form, y=mx+b, just solve for y.

5x+y = 30 Subtract 5x

y = -5x+30

Maurinko [17]3 years ago
4 0

Answer:

y=-5x+30

Step-by-step explanation:

I HOPE THIS HELPS

BRAINLIEST PLSSS I NEED IT SO BAD

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The amount of time workers spend commuting to their jobs each day in a large metropolitan city has a mean of 70 minutes and a st
Xelga [282]

Answer:

81.85% of the workers spend between 50 and 110 commuting to work

Step-by-step explanation:

We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.

We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)

W = \frac{X-μ}{σ} = \frac{X-70}{20}

The values of the cummulative distribution function of the standard normal, which we denote \phi , are tabulated. You can find those values in the attached file.

P(50 < X < 110) = P(\frac{50-70}{20} < \frac{X-70}{20} < \frac{110-70}{20}) = P(-1 < W < 2) = \\\phi(2) - \phi(-1)

Using the symmetry of the Normal density function, we have that \phi(-1) = 1-\phi(1) . Hece,

P(50 < X < 110) = \phi(2) - \phi(-1) = \phi(2) - (1-\phi(1)) = \phi(2) + \phi(1) - 1 =  \\0.9772+0.8413-1 = 0.8185

The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.

Download pdf
7 0
3 years ago
Plsssssss help due today
crimeas [40]
I assume it is the diameter of the outer wheel they are asking for. 

connect OD, which is the radius of the wagon to the outer edge of the wheel. 
OYD is a right triangle. use the hypotenuse theorem:
OY²+YD²=OD²
7²+24²=OD²
OD=√625
OD=25
the radius is 25, the diameter is then 50.

Note: if it is the diameter of the inner circle they are asking for, I don't know. 
6 0
3 years ago
Simplify. 4^3 · 4^4/4^9 A) 41^6 B) 4^2 C) 1/4^2 D) 1/4
VLD [36.1K]
C 1/4>2

cause the and to that is 1/16
6 0
3 years ago
Read 2 more answers
Faces of a three-dimensional figure are any of the __________________, including the bases.
tatiyna

Answer:

A prism is a three-dimensional figure with:

o at least two parallel, congruent faces called bases that are polygons.

o Named by its base

 Examples: triangular prism, rectangular prism

 A pyramid is a three-dimensional figure with:

o one base that is a polygon.

o Its other faces are triangles.

o Examples: triangular pyramid, square pyramid, rectangular pyramid

Step-by-step explanation:

4 0
3 years ago
Show that 1n^ 3 + 2n + 3n ^2 is divisible by 2 and 3 for all positive integers n.
Dmitry_Shevchenko [17]

Prove:

Using mathemetical induction:

P(n) = n^{3}+2n+3n^{2}

for n=1

P(n)  = 1^{3}+2(1)+3(1)^{2} = 6

It is divisible by 2 and 3

Now, for n=k, n > 0

P(k) = k^{3}+2k+3k^{2}

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = (k+1)^{3}+2(k+1)+3(k+1)^{2}

P(k+1) = k^{3}+3k^{2}+3k+1+2k+2+3k^{2}+6k+3

P(k+1) = P(k)+3(k^{2}+3k+2)

Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

divisible by 2 and 3.

Hence, by mathematical induction, P(n) = n^{3}+2n+3n^{2} is divisible by 2 and 3 for all positive integer n.

3 0
3 years ago
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