Answer: The greatest number of rows Li Na can plant is 9.
Step-by-step explanation:
Given: Li Na is going to plant 63 tomato plants and 81 rhubarb plants.
Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.
To find the greatest number of rows Li Na can plant, we need to find the GCF of 63 and 81.
Since , 
Clearly, GCF(63,81)=9
Therefore, the greatest number of rows Li Na can plant is 9.
Answer:For this item, we let x and y be the number of bushels of apple that will be used to produce apple cider and apple juice, respectively. The situation above is best represented by the following equations,
x + y = 18
20x + 15y = 330
The values of x and y from the equations above are 12 and 6, respectively. Therefore, 12 bushels will be used to make apple cider and 6 bushels will be used to make apple juice.
Step-by-step explanation:
Answer: 1 2 3
Step-by-step explanation:
Answer:
5x -12 = 3x +8 (set the two = each other because they are the same length)
2x- 12= 8 (subtract 3x from both sides)
2x = 20 (add 12 to both sides)
x=10 (what x= for both expressions)
5(10) -12 (plug it into the first one to see what the length is and to see they're =
50 - 12 ( I already multiplied, now subtract)
38 (what the length of TR is)
3(10) +8 (plug it in again but into the other expression)
30+8 (multiply and add)
38 (the two have the same answer, so the x-value is correct.)
38+38= 76 (add the lengths of RS and TR and you get the length of TS)
Step-by-step explanation:
I hope this helps :)
Hello,
tan 60°=√3
d/39=tan 60°==>d=39/√3=39√3/3=13√3=22,516660498... (m)
