Create 2 lines thatare parallel to 8x + 2y = 7?

Mathematics

1 answer:

Alinara [238K]2 years ago

7 0

d1 = ax + by + c = 0 and d2= mx + ky + f = 0

if they are parallel :

$\frac{a}{m} = \frac{b}{k} \neq \frac{c}{f}$

8x + 2y = 7

8x + 2y - 7 = 0

8x + 2y -9 = 0
4x + y -6 = 0
16x + 4y - 19 = 0

you can create more whatever you want =)

Hope this helps ^-^

You might be interested in

The graph of the function showing the path of a soccer ball thrown by a goalie in a video game, f(x) = –0.05x2 + 2.5x + 5.2, is

Tju [1.3M]

Answer:

The correct option is 4.

Step-by-step explanation:

The given function is

$f(x)=-0.05x^2+2.5x+5.2$

Where f(x) is height of the ball and x is the distance.

It is a polynomial function with degree 2. All polynomial functions are defined for all real numbers, therefore the mathematical domain of the function is all real numbers.

$-\infty$

Factorize the given function.

$f(x)=-0.05(x^2-50x-104)$

$f(x)=-0.05(x^2-52x+2x-104)$

$f(x)=-0.05(x(x-52)+2(x-52))$

$f(x) = -0.05 (x - 52) (x + 2)$

Put f(x)=0 to find the x intercepts.

$0 = -0.05 (x - 52) (x + 2)$

Equate each factor equal to 0.

$x=52,-2$

Therefore at x=52 and -2, the graph of f(x) intersects x-axis. Before x=-2 and after x=52 the values of f(x) is negative. Height cannot be negative, therefore reasonable domain is lie between -2 to 52.

Distance cannot be negative, therefore the reasonable domain must be positive.

$0\leq x\leq 52$