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3 years ago

PLS HELP ASAPPPp!!! I DONT HAVE TIME I ONLY GOT 5 MINUTES PLS HELP THERES TWO QUESTIONS AHHH IM FREAKING OUT!

Mathematics

2 answers:

ss7ja [257]3 years ago

6 0

Answer:

500, x times 500 = y

Step-by-step explanation:

Question 1: $500, if you look at the table underneath the section for "one" compute it says 500 in the cost section.

Question 2: X times 500 = Y (since for every "x" (computer) there is $500 "y" (cost))

Cerrena [4.2K]3 years ago

3 0

Answer:

1) $500

Step-by-step explanation:

It literally says $500 on the table hope this helps :D

For #2, i cant see the full question.

Hope this helps :D Please hit the crown if you want me to help you on the last one then tell me and make a new question !!!!!!!!!!!!

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3 years ago

A random variableX= {0, 1, 2, 3, ...} has cumulative distribution function.a) Calculate the probability that 3 ≤X≤ 5.b) Find the

olchik [2.2K]

Answer:

a) P ( 3 ≤X≤ 5 ) = 0.02619

b) E(X) = 1

Step-by-step explanation:

Given:

- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:

$F(X) = P ( X =< x) = 1 - \frac{1}{(x+1)*(x+2)}$

Find:

a.Calculate the probability that 3 ≤X≤ 5

b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that

Solution:

- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

$F(X) = P ( 3=$

- The Expected Value can be determined by sum to infinity of CDF:

E(X) = Σ ( 1 - F(X) )

$E(X) = \frac{1}{(x+1)*(x+2)} = \frac{1}{(x+1)} - \frac{1}{(x+2)} \\\\= \frac{1}{(1)} - \frac{1}{(2)}\\\\= \frac{1}{(2)} - \frac{1}{(3)} \\\\= \frac{1}{(3)} - \frac{1}{(4)}\\\\= ............................................\\\\= \frac{1}{(n)} - \frac{1}{(n+1)}\\\\= \frac{1}{(n+1)} - \frac{1}{(n+ 2)}$

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]

E(X) = 1

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