Answer:
vertex at (1, -3)
Step-by-step explanation:
When x = 0
y² + 6y + 1 = 0
y² + 6y + = -1
y² + 6y + 9 = -1 + 9
(y + 3)² = 8 or (-y - 3)² = 8
y + 3 = √8 or -y - 3 = √8
y = - 3 +√8 or y = -3 - √8
(0, - 3 +√8) and (0, -3 - √8)
The mid point between these two is the average
y = ( - 3 + √8 + -3 - √8) / 2 = - 3
y² + 6y + 8x + 1 = 0
(-3)² + 6(-3) + 8x + 1 = 0
9 - 18 + 1 = -8x
- 8 = -8x
x = 1
