X is obviously 1
1x2=2
Entao...(So...)
Please mark as brainliest
Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
If you found this helpful please mark brainliest
Answer:
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Opposite angle of a quadrilateral add up to 180 degrees.
This means Angle A plus Angle C equal 180.
We can solve for X using that, then solve for Angle B.
2x-7 + x +4 = 180
Simplify:
3x -3 = 180
Add 3 to each side:
3x = 183
Divide both sides by 3:
x = 183 /3
x = 61
Now we know x, replace x with 61 in the equation for Angle B:
Angle B = 2x+3 = 2(61) +3 = 122 +3 = 125 degrees.
Answer:
You can split your cracker 4 ways. So each cracker is now 4. Now split your cracker into 4ths, 5•4 = 20! Hope this helps!
Step-by-step explanation:
Your Crackers have those lines, and they split 4 ways. SO this helps make the problem easierto solve.
