Chemical reactions in the material used to make matches, and the cardboard... so hope this helps :)
NOTE: im not to good at this stuff so i rlllllly hope it helps
Explanation:
Case-sensitivity is inherently faster to parse (albeit only slightly) since it can compare character sequences directly without having to figure out which characters are equivalent to each other. It allows the implementer of a class/library to control how casing is used in the code.
Answer:
c. Skewness
Explanation:
Cluster analysis involves analyzing a set of object by grouping the set of objects in such a way that objects in the one group or cluster are more similar to each other than to those in other groups or clusters. The characteristics of data that can strongly affect cluster analysis includes the size, sparseness, scale, etc.
Answer:
-6x^4 + 7x^3 + 17x^2 -4x
Explanation:
( f x g )( x )
Substitute
[( -2x^2 + 5x -1 )( 3x + 4 )]( x )
Use the Distributive Property
[-2x^2( 3x) + 5x( 3x) - 1( 3x) -2x^2( 4) + 5x (4) -1 (4)] (x)
Simplify
( -6x^3 + 7x^2 + 17x -4)(x)
Distributive Property
-6x^4 + 7x^3 + 17x^2 -4x
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
