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Sliva [168]
3 years ago
11

Michael needs at least $150 to buy a new pair of Jordans shoes. He has already

Mathematics
1 answer:
damaskus [11]3 years ago
3 0
Y=15x+45
150=15x+45
-45 -45
105=15x
105/15=15x/15
7=x
7 hours
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1.) The island shown has a population of 12,175 people. Find the population
miv72 [106K]

Answer:

Population density = 148.22\ \text{people per square kilometer}

Step-by-step explanation:

The attached figure shows the dimension of an island.

Population density is equal to total population per unit land area.

Firstly we will find the area of the triangle using Pythagoras theorem as follows :

H^2=B^2+P^2

H is Hypotenuse, B is base and P is perpendicular

B=\sqrt{H^2-P^2} \\\\B=\sqrt{(18.5)^2-(11.1)^2} \\\\B=14.8\ km

Area of triangle is given by :

A=\dfrac{1}{2}\times b\times P\\\\A=\dfrac{1}{2}\times 14.8\times 11.1\\\\A=82.14\ km^2

\text{Population density}=\dfrac{\text{Total population}}{\text{land area}}\\\\=\dfrac{12175 }{82.14}\\\\=148.22\ \text{people per square kilometer}

Hence, the population density is 148.22\ \text{people per square kilometer}.

7 0
3 years ago
Ayo who gon win a fight yo mom or goku
kkurt [141]

Answer:

my mom will win the fight

6 0
3 years ago
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What is the reciprocal of 100
ale4655 [162]

Answer:

0.01

Steps:

The definition of "reciprocal" is simple. To find the reciprocal of any number, just calculate "1 ÷ (that number)." For a fraction, the reciprocal is just a different fraction, with the numbers "flipped" upside down (inverted). For instance, the reciprocal of 3/4 is 4/3

8 0
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The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

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3 years ago
Please answer all the questions above.
Fed [463]

Answer:

hope it was helpful!! You are welcome to ask any question

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