Answer:
Hi there!
The answer for number 13 is 2.
I picked two coordinates: (1,1) and (2,3)
Then I used the (y1-y)/(x1-x) equation to get 2.
The answer for number 14 is 2.
I picked two coordinates: (1,0) and (2,2)
Then I used the (y1-y)/(x1-x) equation to get 2.
Answer:
At time t = 0.408 sec diver will be at maximum height
Step-by-step explanation:
We have given equation of the height 
We know that velocity is the rate of change of distance with respect to time
So 
At maximum height velocity will be zero
So 
t = 0.408 sec
So at time t = 0.408 sec diver will be at maximum height
Means multiply 2 3/2×6 ok
The picture in the attached figure
we have
arc XV = 68°∠YUV = 36°
we know that
The measure of the external angle is the semidifference of the arcs that it covers.
therefore
∠YUV =[arc VY-arc XV]/2
arc VY=[2*∠YUV]+arc XV----------> [2*36]+68---------> 140°
the answer is
the measure of arc VY is 140°
Answer:
I took the test, Its B) 41.1