Answer:
Option C is correct.
Step-by-step explanation:
y = x^2-x-3 eq(1)
y = -3x + 5 eq(2)
We can solve by substituting the value of y in eq(2) in the eq(1)
-3x+5 = x^2-x-3
x^2-x+3x-3-5=0
x^2+2x-8=0
Now factorizing the above equation
x^2+4x-2x-8=0
x(x+4)-2(x+4)=0
(x-2)(x+4)=0
(x-2)=0 and (x+4)=0
x=2 and x=-4
Now finding the value of y by placing value of x in the above eq(2)
put x =2
y = -3x + 5
y = -3(2) + 5
y = -6+5
y = -1
Now, put x = -4
y = -3x + 5
y = -3(-4) + 5
y = 12+5
y =17
so, when x=2, y =-1 and x=-4 y=17
(2,-1) and (-4,17) is the solution.
So, Option C is correct.
Answer:
(2,-5) and (2,1).
Step-by-step explanation:
We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.
A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.
Standard form of a circle is
where, (h,k) is center and r is the radius.
Now, put x=2.
Taking square root on both sides.
So, the y-coordinates of the points are -5 and 1.
Therefore, the required points are (2,-5) and (2,1).
Answer:
3
Step-by-step explanation:
you first need to convert 9 hours into minutes:
9*60=<u>5</u><u>4</u><u>0</u> minutes
162 jumps ---in--- 540 minutes
? jumps ---in--- 10 minutes
?= (10*162)/540
?= 3
5/3+2/5=25/15+6/15=31/15=2 1/15
2 1/15 or 31/15
