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Annette [7]
3 years ago
9

Is -7/3 equivalent to -7/-3?

Mathematics
1 answer:
masya89 [10]3 years ago
8 0

Answer:

no

Step-by-step explanation:

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Higher order thinking. Rectangular prism can have a volume of 12 cubic units
MissTica

Answer:

  see below

Step-by-step explanation:

Volume is the product of the three dimensions: length, width, and height.

The numbers in the three columns need to have a product of 12. Your knowledge of multiplication tables lets you fill in the missing factors easily.

8 0
3 years ago
Which expression fits this description?
Romashka [77]

Answer:

d is your Answer .............

8 0
3 years ago
At a sale, coats were sold for $118 each. If the coats originally cost $200 each, what percentage of its original price was a co
pochemuha

rAnswer:

Step-by-step explanation:

20$

5 0
2 years ago
Write 2^8 * 8^2 * 4^-4 in the form 2^n
Eva8 [605]

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

<h3>What are exponential forms?</h3>

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

<u>For example:</u>

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

  • a is the base, and
  • 4 is the power.

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power. 

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }

\mathbf{= 2^8\times (2^6) \times (2^{-8}) }

\mathbf{= 2^{8+6+(-8)}}

\mathbf{= 2^{6}}

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

Learn more about exponential forms here:

brainly.com/question/8844911

#SPJ1

4 0
2 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
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