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3 years ago

If 1/3 of a pound of jellybeans is shared equally between 3 brothers, how many pounds of jellybeans each brother received

Mathematics

1 answer:

I am Lyosha [343]3 years ago

6 0

Answer:

1/9 lbs

Step-by-step explanation:

1/3 ÷ 3

covert whole number to fraction

1/3 ÷ 9/3

copy dot flip

1/3 × 3/9

3/27

1/9

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PLEASE HELP<br><br> Graph the ordered pairs for y = 3x + 3 using r = {-2, 1, 2}.

Fed [463]

9514 1404 393

Answer:

(-2, -3), (1, 6), (2, 9) are plotted in the attached graph

Step-by-step explanation:

For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).

For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).

For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).

The graph is attached.

5 0

2 years ago

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Anyone know what the answer is

Mars2501 [29]

Answer:

22,-15 ................ maybe

4 0

3 years ago

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 22 Pennies 27 Dimes 9 Nickels

kap26 [50]

Answer:

$P(Penny\ and\ Dime) = \frac{9}{116}$

Step-by-step explanation:

Given

$Pennies = 22$

$Dimes = 27$

$Nickels = 9$

$Quarters = 30$

Required

$P(Penny\ and\ Dime)$

This is calculated as:

$P(Penny\ and\ Dime) = P(Penny) * P(Dime)$

Since it is a selection without replacement, the computation is:

$P(Penny\ and\ Dime) = \frac{Penny}{Total} * \frac{Dime}{Total-1}$

So, we have:

$P(Penny\ and\ Dime) = \frac{22}{22+27+9+30} * \frac{Dime}{22+27+9+30-1}$

$P(Penny\ and\ Dime) = \frac{22}{88} * \frac{27}{87}$

$P(Penny\ and\ Dime) = \frac{1}{4} * \frac{9}{29}$

$P(Penny\ and\ Dime) = \frac{9}{116}$

5 0

2 years ago

Who can solve this <br>2xy if x=5 and y=-3

Softa [21]

Answer:

-30

Step-by-step explanation:

2*5 is 10

10*-3 is -30

8 0

3 years ago

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Polygon ABCD is dilated, rotated, and translated to form polygon A′B′C′D′. The endpoints of AB are at (0, -7) and (8, 8), and th

Anton [14]

Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

First, find AB and A'B' by the formula:

$AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}= \sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17,\\ \\A'B'=\sqrt{(x_{B'}-x_{A'})^2+(y_{B'}-y_{A'})^2}= \sqrt{(2-6)^2+(1.5-(-6))^2}=\sqrt{4^2+7.5^2}=\sqrt{16+56.25}=\sqrt{72.25}=8.5.$

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.

8 0

3 years ago