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3 years ago

Answers for both boxes please

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

3 0

Answer:

(-3, -6)

Step-by-step explanation:

y=2x

-3x-15=y

Use Substitution Method

-3x-15=2x

+3x +3x

-15=5x

/5 /5

-3=x

y=2x

y=2(-3)

y=-6

In-s [12.5K]3 years ago

3 0

Answer:

(-3, -6)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Solving systems using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x

-3x - 15 = y

Step 2: Solve for x

Substitute in y: 2x = -3x - 15
Isolate x terms: 5x = -15
Isolate x: x = -3

Step 3: Solve for y

Define equation: y = 2x
Substitute in x: y = 2(-3)
Multiply: y = -6

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ohaa [14]

Answer:

Step-by-step explanation:

(f-g)(x) = f(x) - g(x)

=3x^3+8x^2-7x-4-(2x-6)

=3x^3+8x^2-9x+2

4 0

3 years ago

sin alpha = 7/25, alpha lies in quadrant ii, and cos beta = 2/5, beta lies in quadrant i. find cos(alpha-beta).

Ilia_Sergeevich [38]

Answer:

Therefore $\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

Step-by-step explanation:

Given values are

$\sin \alpha=\frac{7}{25}$

$\cos \beta=\frac{2}{5}$

$\sin^2x+\cos^2=1$

$\cos \alpha=\sqrt{1-\sin^2\alpha}$

$\cos \alpha=\sqrt{1-(\frac{7}{25})^2}$

$\cos \alpha=\sqrt{1-\frac{49}{625}}$

$\cos \alpha=\sqrt{\frac{576}{625}}$

$\cos \alpha=\frac{24}{25}$

$\sin \beta=\sqrt{1-\cos^2\beta}$

$\sin \beta=\sqrt{1-(\frac{2}{5})^2}$

$\sin \beta=\sqrt{1-\frac{4}{25}}$

$\sin \beta=\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta$

$\cos(\alpha-\beta)=\frac{24}{25}\times\frac{2}{5}+\frac{7}{25}\times\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

7 0

3 years ago

Vika [28.1K]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-----------------------------\\\\
\cfrac{s^3}{s^3}\implies \cfrac{216}{1000}\implies \cfrac{\sqrt[3]{216}}{\sqrt[3]{1000}}\implies \cfrac{s}{s}\impliedby \textit{similarity ratio}$

and simplify it away

3 0

3 years ago

A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" ac

Andrei [34K]

Answer:

a) v = 12.21m/s

a = 4.07 m/s²

b)v = 11.24m/s

a = 3.75 m/s²

Step-by-step explanation:

a) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

v₀ = 0
s₀ = 0
a = ?
v = ?
t = 3s
s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 100

s₀ = x

v = v

t = 9.69 - 3 = 6.69s

s = s₀ + vt

100 = x + v*6.69

100 = x + 6.69v

As x = 3v/2

100 = 3v/2 + 6.69v

100 = 1.5v + 6.69v

100 = 8.19v

v = 12.21m/s

a = v/3 = 4.07 m/s²

b) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

v₀ = 0
s₀ = 0
a = ?
v = ?
t = 3s
s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 200

s₀ = x

v = v

t = 19.30 - 3 = 16.30s

s = s₀ + vt

200 = x + v*16.3

100 = x + 16.3v

As x = 3v/2

200 = 3v/2 + 16.3v

200 = 1.5v + 16.3v

200 = 17.8v

v = 11.24m/s

a = v/3 = 3.75 m/s²

8 0

3 years ago

Imaginary numbers (-3-5/)(-3+5) Answer choices: 1. 34 2. 34-30i 3. -16

lisabon 2012 [21]

Answer:

the answer to the question is -16

7 0

3 years ago

Answers for both boxes please ​

Answers for both boxes please