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3 years ago

What does the quadratic formula solve for

1 answer:

8 0

The quadratic formula solves for X so u can plot it on a graph. it solves for X by subtracting and another way by Adding so you get 2 x's

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Please help I need an answer fast

sp2606 [1]

All you need to do is use the formula to solve. What I do is I plug in the information that I know, and then I just solve. In this case it would be:

V= (4)
- pie(3.14)*4.8(cubed)
3

I hope I was a good help, and if you still need help, come to my page and ask the question on specifically what you need help with. :D

5 0

3 years ago

the three median of a triangle intersect as a point. which measurements could represent the segments of one of the medians? 2 an

topjm [15]

2 & 3 is your answer

6 0

3 years ago

Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha

irinina [24]

Answer:

$n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401$

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Solution to the problem

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

The margin of error desired for this case is $ME= \pm 0.02$ equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is $\hat p =0.5$

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.96$

Now we have all the values needed and if we replace into equation (b) we got:

$n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401$

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0

3 years ago

(05.03)An irregular polygon is shown below:

SVEN [57.7K]

9units sorry for not showing work though but glad I can help

7 0

3 years ago

Help me please <br><br> will get rewared brainly if correct answer

larisa [96]

Well, split it into 3 shapes

21 x 10 = 210

3 x 6 = 18

2 x 6 = 12

210 + 18 + 12 = 240 square cm

imahe for more context

plzzz give me brainliest

5 0

3 years ago