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3 years ago

URGENT HELP! URGENT I WILL GIVE ALL OF MY POINTS

Mathematics

2 answers:

rjkz [21]3 years ago

7 0

Answer:

|a| > |b|

Step-by-step explanation:

When you have absolute values you remove the negative from number.

So false true, false

anastassius [24]3 years ago

6 0

Answer:

false, true, false

Step-by-step explanation:

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Solve the given inequality and graph the solution on a number line -x/2 + 3/2 + < 5/2 .

liq [111]

Answers in Image attached

Hope this helps

5 0

3 years ago

Read 2 more answers

1.) -2(6 - 2x) = 4(-3 + x)<br> 2.) 5 - 1(2x + 3) = -2(4 + x)

Scrat [10]

Let's solve your equation step-by-step.

Question 1: −2(6−2x) =4(−3+x)

Step 1: Simplify both sides of the equation.

−2(6−2x) =4(−3+x)

(−2) (6) +(−2) (−2x) =(4)(−3)+(4)(x)(Distribute)

−12+4x=−12+4x

4x−12=4x−12

Step 2: Subtract 4x from both sides.

4x−12−4x=4x−12−4x

−12=−12

Step 3: Add 12 to both sides.

−12+12=−12+12

0=0

Answer: All real numbers are solutions.

Question 2:

Let's solve your equation step-by-step.

5−1(2x+3) =−2(4+x)

Step 1: Simplify both sides of the equation.

5−1(2x+3) =−2(4+x)

5+(−1) (2x) +(−1) (3) =(−2) (4)+(−2)(x)(Distribute)

5+−2x+−3=−8+−2x

(−2x) +(5+−3) =−2x−8(Combine Like Terms)

−2x+2=−2x−8

Step 2: Add 2x to both sides.

−2x+2+2x=−2x−8+2x

2=−8

Step 3: Subtract 2 from both sides.

2−2=−8−2

0=−10

Answer: There are no solutions.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=obtain%20the%20fourier%20expansion%20for%20sin%20ax%20in%20the%20interval%20-%20%7C%20%20%20%5

Norma-Jean [14]

I really do not get it . It’s this a question ? If so can you be a little more specific .

4 0

3 years ago

What is the slope of the line that contains these points?

Rus_ich [418]

For the first one it might be 26? i’m not so sure

8 0

3 years ago

Write a polynomial function, p(x) with degree 3 that has p(7)=0

MArishka [77]

Answer:

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

$(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}$

Take a = x

b = 7

Substitute in the identity we get

$(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343$

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

4 0

3 years ago