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3 years ago

What is the answer the file at the bottom

Mathematics

2 answers:

navik [9.2K]3 years ago

6 0

The first part is 3. The second is 12

prisoha [69]3 years ago

6 0

Answer:

the first one is three and the second one is 12

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Find the perimeter.

Scorpion4ik [409]

Answer:

7 1/3 inches

Step-by-step explanation:

2 (1 3/4 + 1 11/12)

9+11

3/4+11/12= -------------

20/12

=1 2/3+ 2

2(3 2/3)

= 7 1/3

7 0

2 years ago

Solve 2x+3y=6 for y Answers listed: y=-2/3x+2 y=2/3x-2 y=2x-3 y=2x+6

iren2701 [21]

2x + 3y = 6 <=>

3y = -2x + 6 <=>

y = -2/3x + 6/3 <=>

y = -2/3x + 2

The answer is the first one.

4 0

3 years ago

Read 2 more answers

Factor of 169 and 9 squared

emmasim [6.3K]

Answer:

The greatest common factor of 169 and 81 is 1.

Step-by-step explanation:

9 squared is 81 and the greatest common factor of 169 and 81 is one. They have no other common factors. Please mark me brainliest and I hope this helps!

3 0

3 years ago

What is 20-2w^2 when, w= 3

kow [346]

Answer:

Step-by-step explanation:

Use order of operations PEMDAS

3^2 = 9 * 2 = 18

20-18= 2

7 0

3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

2 years ago