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3 years ago

Help!! help!! help!! help!! help!! help!! help!! help!! help!!

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

Given the simultaneous equation;

$\frac{a}{b} - \frac{b}{2} = 10\\a - b = 29$

From 2;

a = 29 + b ....3

Substitute 3 into 1;

$\frac{29+b}{b} - \frac{b}{2} = 10\\\frac{2(29+b)-b^2}{2b} = 10\\\frac{58+2b-b^2}{2b} = 10\\58+2b-b^2 = 20b\\b^2-2b-58 = -20b\\b^2-2b+20b -58 = 0\\b^2+18b-58 = 0\\$

Factorize

b = -18±√18²-4(-58)/2

b = -18±√324+232/2

b = -18±√556/2

b = -18±23.58/2

b = -18-23.58/2 and -18+23.58/2

b = -41.58/2 and 5.58/2

b = -20.79 and 2.79

Since a = 29 + b

when b = -20.79

a = 29 - 20.79

a = 8.21

<em>Hence the solution to the system of equation is (8.21, -20.79)</em>

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What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

dezoksy [38]

Answer:

$A" = (3,2)\ \ B" = (-1,1)\ \ C" =(-3,4)\ \ D =(-1,4)$

Step-by-step explanation:

Given [Missing]

$A = (-3,4)$

$B = (1,3)$

$C =(3,6)$

$D =(1,6)$

The first transformation: reflection across the y-axis.

The rule is: $(x,y)==>(-x,y)$

So:

$A = (-3,4)$ ==> $A' = (3,4)$

$B = (1,3)$ ==> $B' = (-1,3)$

$C =(3,6)$ ==> $C' = (-3.6)$

$D =(1,6)$ ==> $D' = (-1,6)$

Translation 2 units down

The rule is: $(x,y)==>(x,y-2)$

So:

$A' = (3,4)$ ==> $A" =(3,4-2) =(3,2)$

$B' = (-1,3)$ ==> $B" = (-1,3-2) = (-1,1)$

$C' = (-3.6)$ ==> $C" = (-3,6-2) = (-3,4)$

$D' = (-1,6)$ ==> $D" =(-1,6-2) = (-1,4)$

Hence:

$A" = (3,2)\ \ B" = (-1,1)\ \ C" =(-3,4)\ \ D =(-1,4)$

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3 years ago

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cluponka [151]

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Step-by-step explanation:

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3 years ago

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andrew-mc [135]

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3 years ago

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denis23 [38]

Answer:

option B 5

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Step-by-step explanation:

Given in the question an inequality

x² > 16

Step 1

Take square root on both sides of inequality

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3 years ago

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nordsb [41]

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