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Xelga [282]
3 years ago
10

A guy wire for a tree is 14 feet long. Making a 41° angle with the ground, how far is the base of the tree from the stake anchor

ing the wire?​
Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0
Draw the picture; you have a right triangle. The guy wire is the hypotenuse
You want the length of the base when the side opposite the 41 degree angle
is the tree.
You have an angle and the hypotenuse; the base is the side adjacent to the
41 degree angle.
EQUATION:
cos(41) = adjacent/hypotenuse = x/14
14cos(41) = x
x = 10.57 ft
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What's the difference between 126 1/4 78 2/3
Stels [109]
Difference means subtract, so we use subtraction:

*first we need to make the fractions have the same denominator

1/4 = 3/12
2/3 = 8/12

126(3/12) - 78(8/12)
*since the fraction in the first term is smaller than the second, make it improper

125(15/12) - 78(8/12)

now simply subtract:

125 - 78 
= 47

15 - 8 
= 7
* this is now (7/12)

now put them back together:

47(7/12) 

That's the final answer!
3 0
3 years ago
Jasmine has 4 glass ornanents:green,orange,brown,and purple.How many ways can she hang them in a row so that the green and brown
tino4ka555 [31]
The best way to solve this is by giving a visual idea of the glass ornaments. so We will have letter G represent Green, O for Orange, B for Brown, P for Purple.
Sample 1:G,O,B,P
Sample 2:G,P,O,B
Sample 3:P,G,O,B
Sample 4:O,G,P,B
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4 0
2 years ago
Read 2 more answers
Will mark Brainlest hellpppp​
Anna007 [38]

h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

h(2) =  \frac{2 {(4)}  - 2 + 1}{6 - 2}

h(2) =  \frac{ 8  - 1}{4}

h(2) =  \frac{7}{4}

h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

5 0
3 years ago
The function, f(x)=70n-400, models the profit of the instructor of a guitar class per month, where n is the number of students e
zimovet [89]

profit=f(x)

so solve for f(x)=1000

1000=70n-400

add 400 to both sides

1400=70n

divide both sides by 70

20=n

20 students need to be enrolled to make a profit of 1000.00

4 0
2 years ago
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Paladinen [302]
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8 0
2 years ago
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