Answer:
(x+12)^2=84
Step-by-step explanation:
x^2+24x+60=0
x^2+24x=-60
x^2+24x+(24/2)^2=-60+(24/2)^2
(x+24/2)^2=84
(x+12)^2=84 (ans)
Answer:
R { - 6, 6 }
Step-by-step explanation:
To find the range substitute the values of x from the domain into f(x)
f(- 1) = - 4(- 1) + 2 = 4 + 2 = 6
f(2) = - 4(2) + 2 = - 8 + 2 = - 6
Range { - 6, 6 }
Answer:
what do u mean sing like can you rewrite what we suppose to look in it.
Step-by-step explanation:
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)