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mrs_skeptik [129]
2 years ago
11

100

Mathematics
1 answer:
lesya [120]2 years ago
8 0

Using the graph and the percentile concept, it is found that:

  • The 20th percentile represents about 67 inches, meaning that 20% of the people in the group are shorter than 67 inches.

<h3>What is the percentile concept?</h3>

When a measure is in the xth percentile of a data-set, it is greater than x% of the measures and lesser than (100 - x)%.

In the graph:

  • The x-axis is the height.
  • The y-axis is the percentile.
  • When y = 20, x = 67, which means that:

The 20th percentile represents about 67 inches, meaning that 20% of the people in the group are shorter than 67 inches.

You can learn more about the percentile concept at brainly.com/question/24495213

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r-ruslan [8.4K]

Answer:

- 3.5x =  - 35 \\ x =  \frac{ - 35}{ - 3.5}(  -  \div  -  =  + ) =  \frac{35}{35 \times .1}  \\  =  \frac{1}{.1}  = 10 \\ x = 10 \\ thank \: you

7 0
2 years ago
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Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

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Answer:

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This eliminates B and D

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Please help!
motikmotik

Answer:

A.

Step-by-step explanation:

Step 1: Write equation

x² - 8x = 3

Step 2: Solve for <em>x</em>

  1. Complete the Square: x² - 8x + 16 = 3 + 16
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Answer:

C) 35

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