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3 years ago

Which function has a greater y value if x=2 O Blue Red

Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

Guessing the answer should be the blue one because it is going up the graph steeper.

Step-by-step explanation:

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5/6k=1/6 solve for k

Molodets [167]

5/6k = 1/6
k = 1/6 / 5/6 = 1/6 * 5/6 after you multiply your solution for K = 1/5

7 0

3 years ago

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Solve for x <br><br>x^3 - 3x = 0

artcher [175]

Answer:

x^3-3x=0

+3x

x^3=3x

ok so that means that that number cubed is the same as a number squared so

x = 0

x = -sqrt(3)

x = sqrt(3)

im going say the answer is mostly likely 0 but it could be the other ones

Hope This Helps!!!

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2 years ago

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X+4 divided by x^2+16<br><br> Why can't it be simplified?

KonstantinChe [14]

Let's try to simplify x^2 + 16. It's a sum of two squares:

x^2 + 16 = 0

x^2 = -16

The problem is, we can't take a square root of a negative. This is where imaginary numbers come in.

Remember that square roots have a plus or minus symbol outside:

±√-16 = ±4i

Our two roots are 4i and -4i. Therefore, the trinomial simplifies to:

(x + 4i)(x - 4i)

If we attempt to divide x + 4 by these two binomials, we will find that 4 and 4i are not like terms. Therefore, we can't simplify this expression.

8 0

2 years ago

I need help please and thank you

azamat

Answer:

I believe it's B ............

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2 years ago

A quadratic equation is shown below:

sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

$3x^{2}-11x+10=0$ has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

$\frac{d}{dx}(3x^{2}-11x+10)=6x-11$

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

$x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

$x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}$

6 0

3 years ago