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3 years ago

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the area of a parallelogram is 36x^6y^5. if the base of the parallelogram is 3xy^2 units,what is the height of the parallelogram

1 answer:

erastova [34]3 years ago

3 0

Answer:

h = 12x^5y^3

Step-by-step explanation:

The area of a parallelogram is found using A = b*h. Substitute the values given and solve for h.

A = b*h

36x^6 y^5 = 3xy^2 * h

36x^6 y^5 ÷ 3xy^2 = h

12x^5y^3 = h

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Find the length of the missing side of necessary round to the nearest tenth

Misha Larkins [42]

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Step-by-step explanation:

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3 years ago

How do you solve this? A and B

svp [43]

An adult polar bear is 8 times longer than a newborn.
Newborn= 12 1/2 ft
Multiply this by 8.
But first you have to turn the fraction
12 1/2 into an improper fraction. To do this you have to multiply the denominator, 2, by the whole number, 12, and add the numerator to the product, which totals to 25. The fraction is 25/2. (25/2 * 8/1)= 100 in simplified. 100 inches= 8 1/3 ft long
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8 0

3 years ago

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Q:14 which expression is equivalent to m-4/m+4 divided by (m+2)

jek_recluse [69]

Answer is the first option

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3 years ago

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Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

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Answer:

Step-by-step explanation:

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3 years ago

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