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tester [92]
3 years ago
14

If 35men can do a piece of work in 45days,How long should 27men takes​

Mathematics
1 answer:
Ilya [14]3 years ago
5 0

Answer:

37

Step-by-step explanation:

what's the difference between 35 and 45 .

10

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What does parallelepiped focus on
charle [14.2K]

A parallelepiped focuses on three-dimensional figures formed by six parallelograms.

<h3>How to explain the parallelepiped?</h3>

A parallelepiped shape has the following features

  • They are three-dimensional figures
  • They are formed by 6 parallelograms
  • Opposite parallelograms are congruent

Think of a cube or a cuboid.

Notice that they contain squares and rectangles

A parallelepiped is to a parallelogram as a square is to a cube and a rectangle to a cuboid

Read more about parallelepiped at:

brainly.com/question/3050890

#SPJ11

7 0
2 years ago
Read 2 more answers
The cost of 8 muffins and 2 quarts of mil is $18. The cost of 3 muffins and 1 quart of milk is $7.50 hos much does 1 muffin and
emmasim [6.3K]

Answer:

The cost of the 1 muffin is $1.5 and 1 quart of milk cost is $3 .

Step-by-step explanation:

Let us assume that the cost of one muffins be x.

Let us assume that the cost of one 1 quarts of milk be y.

As given

The cost of 8 muffins and 2 quarts of mil is $18.

Than the equation becomes

8x + 2y = 18

As given

The cost of 3 muffins and 1 quart of milk is $7.50.

Than the equation becomes

3x + 1y = 7.50

Two equations are

8x + 2y = 18  and 3x + 1y = 7.50

Multiply  3x + 1y = 7.50 by 2 and subtracted from 8x + 2y = 18 .

Thus

8x - 6x + 2y - 2y = 18 - 15

2x  =  3

x = \frac{3}{2}

x = 1.5

Put x = 1.5 in 3x + 1y = 7.50

3 × 1.5 + y = 7.50

y = 7.50 - 4.5

y = 3

Therefore the cost of the 1 muffin is $1.5 and 1 quart of milk cost is $3 .

3 0
3 years ago
Gene is playing a game with a bag of marbles. 3 of the marbles are blue, 4 are green, and 7 are yellow. See below for awarded pr
jek_recluse [69]

Answer:

<h2><em>$23.5</em></h2>

Step-by-step explanation:

Gene is playing a game with a bag of marbles. If 3 of the marbles are blue, 4 are green, and 7 are yellow and awarded prices for the marbles are $2 green $0.5 yellow $4 blue, the expected payout for Gens game is expressed as shown;

If a blue marble costs $4, 3 blue marbles will cost 3*$4 = $12

If a green marble costs $2, 4 green marbles will cost 4*$2 = $8.0

If a yellow marble costs $0.5, 7 yellow marbles will cost 7*$0.5 = $3.5

Total payout for Gene's game will be the equivalent to $12+ $8 + $3.5 = $23.5.

<em>Hence Gene expected cost will be $21.5</em>

5 0
3 years ago
Pls help me with this pictur​
Bond [772]

Answer: The answer would be C.

Step-by-step explanation:

Explanation : Enzo has 7 pesos, and a ballpoint pen is 2 pesos + an additional 2 pesos, he spent 4, now we have 3 left. A notebook is 3 pesos - a single peso, he just spend 2 more pesos leaving him with only 1 peso left. The crayons cost 2 pesos - a single peso which means he used his remaining peso, 4 + 2 + 1 = 7.

7 0
2 years ago
The scores of individual students on the American College Testing (ACT) Program College Entrance Exam have a normal distribution
tekilochka [14]

Answer:

The probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

Step-by-step explanation:

Xi~N(18.6, 6.0), n=400, Yi~Ber(p); Z~N(0, 1);

P(0\leq X\leq 19.0)=P(\frac{0-\mu}{\sigma} \leq \frac{X-\mu}{\sigma}\leq \frac{19-\mu}{\sigma}), Z= \frac{X-\mu}{\sigma}, \mu=18.6, \sigma=6.0

P(-3.1\leq Z\leq 0.0667)=\Phi(0.0667)-\Phi (-3.1)=\Phi(0.0667)-(1-\Phi (3.1))=0.52790+0.99903-1=0.52693

P(Xi≥19.0)=0.473

\{Yi=0, Xi<  19\\Yi=1, Xi\geq  19\}

p=0.473

Yi~Ber(0.473)

P(\frac{1}{n}\displaystyle\sum_{i=1}^{n}X_i\geq 19)=P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)

Based on the Central Limit Theorem:

\displaystyle\sum_{i=1}^{n}X_i\~{}N(n\mu, \sqrt{n}\sigma),\displaystyle\sum_{i=1}^{400}X_i\~{}N(7440, 372)

Then:

P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)=1-P(0

P(\displaystyle\sum_{i=1}^{n}Y_i=1)=P(\displaystyle\sum_{i=1}^{400}Y_i=1)

Based on the Central Limit Theorem:

\displaystyle\sum_{i=1}^{400}Y_i\~{}N(400\times 0.473, \sqrt{400}\times 0.499)=\displaystyle\sum_{i=1}^{400}Y_i\~{}N(189.2; 9.98)

P(\displaystyle\sum_{i=1}^{400}Y_i=1)\~{=}P(0.5

Then:

the probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

7 0
3 years ago
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