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Svetlanka [38]
3 years ago
8

Ella invested $2,700 in an account paying an interest rate of 5.4% compounded

Mathematics
2 answers:
8090 [49]3 years ago
8 0

Answer:

7  

Step-by-step explanation:

Dmitry [639]3 years ago
3 0

Answer:

<em>The account will take 7 years to reach a value of $4,020</em>

Step-by-step explanation:

<u>Compound Interest </u>

When it occurs interest in the next period is then earned on the principal sum plus previously accumulated interest.

The formula is:

{\displaystyle A=P\left(1+{\frac {r}{n}}\right)^{nt}}

Where:

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

Ella invested P=$2,700 in an account with an interest rate of r=5.4% (0.054) compounded monthly. Since there are 12 months in a year, n=12.

It will be calculated when will the account have a value of A=$4,020. Substituting all the values in the formula:

{\displaystyle 4,020=2,700\left(1+{\frac {0.054}{12}}\right)^{12t}}

Calculating:

{\displaystyle 4,020=2,700\left(1.0045)^{12t}}

Dividing by 2,700:

{\displaystyle \frac{4,020}{2,700}=\left(1.0045)^{12t}}

To solve this equation for t, we need to apply logarithms:

{\displaystyle \log\frac{4,020}{2,700}=\log\left(1.0045)^{12t}}

Applying the logarithm power rule:

\displaystyle \log\frac{4,020}{2,700}=12t\log 1.0045

Dividing by 12log 1.0045:

\displaystyle t=\frac{\log\frac{4,020}{2,700}}{12\log 1.0045}

Calculating:

t= 7.39 years

Rounding to the nearest year, the account will take 7 years to reach a value of $4,020

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\huge\mathfrak\colorbox{white}{}

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