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Find the value of x. help with geometry pls

Ivan

Answer:

Find the value of x:-

To find Y, use Pythagorean theorem:- $c^{2} =a^{2} +b^{2}$

$(2.1)^{2} =y^{2} +(1.4)^{2}$

$2.1^{2}=4.41$

$1.4^{2} =1.96$

$4.41=y^{2} +1.96$

subtract 1.96 from both sides

$2.45=y^{2}$

$y=1.5652$

Now, to find x:-

$x=y+y$

$= 1.5632+1.5652$

$x=3.1 \: ft$

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16. Find the value of y.

devlian [24]

y + (2x -12) = 180 (since they are supplementary angles)

(2x-12) = 96 ( since they are alternate exterior angle)

2x = 96 + 12

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