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sasho [114]
3 years ago
11

GEOMETRY. What am I suppose to do?

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

1= 115 2=65

Step-by-step explanation:

the two lines with the red arrows are parallel, meaning the angles they create from the line running through them in this case are equal. they're also equal to 180. so, we know that angle 1 is 115 because it's given, and 180-115=65.

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Please please help <br> |q-8|=14
Maslowich

Answer:

22, -6

Step-by-step explanation:

q-8=14 or 8-q=14

q=22 or q= -6

4 0
3 years ago
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Show that if you pick three marbles from a jar containing only blue and red marbles, you must get a pair of blue or a pair of re
zimovet [89]
Isn't that not possible? A pair would be two not three...
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3 years ago
The ratio of the number of coins to the number of notes Mrs James has in her purse is 2 : 5.
Ivahew [28]

Answer:

85 notes

Step-by-step explanation:

2 coins : 5 notes

1 coin   :    2.5 notes

34 coins : __ notes

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3 0
4 years ago
Can anyone help me with these two plz
Evgen [1.6K]

Answer:

Part 1) The scale factor is 1.5

Part 2) The altitude QS is 4\ units

Part 3) The scale factor is \frac{2}{3}

Part 4) The value of x is 12\ units

Part 5) The perimeter of ABCDE is 46\ units

Step-by-step explanation:

Part 1) Find the scale factor of triangle TQR to triangle NQP

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

z-----> the scale factor

z=\frac{NP}{RT}

substitute the values

z=\frac{24}{16}=1.5

Part 2) Find the length of the altitude QS

we know that

To find the altitude QS, divide the altitude of triangle NQP by the scale factor

so

QS=\frac{6}{1.5}=4\ units

Part 3) Find the scale factor of FGHJK to ABCDE

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

z-----> the scale factor

z=\frac{AB}{FG}

substitute the values

z=\frac{10}{15}=\frac{2}{3}

Part 4) Find the value of x

we know that

The value of x is equal to multiply the length side FK by the scale factor

so

AE=FK(z)

substitute the values

AE=18(2/3)=12\ units

Part 5) Find the perimeter of ABCDE

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of ABCDE

y-----> the perimeter of FGHJK

z=\frac{x}{y}

we have

z=\frac{2}{3}

y=15+9+12+15+18=69\ units

substitute the values

z=\frac{x}{y}

x=(z)(y)=\frac{2}{3}(69)=46\ units

6 0
4 years ago
A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate
Shkiper50 [21]

The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

\implies Q'+\dfrac Q{300+3t}=4

which is a linear ODE in Q(t). Multiplying both sides by (300+3t)^{1/3} gives

(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

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\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

\implies Q(t)=300+3t+C(300+3t)^{-1/3}

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100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

and we get the particular solution

Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

5 0
3 years ago
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