Answer: the on to the bottom left
Step-by-step explanation: c would be right because you have a positive slope
SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Answer:
• 2/3|2 -x| = 1/15
• |2 -x| = 1/10
• 1/5 +|4/3 -2/3x| = 4/15
Step-by-step explanation:
Starting with the given equation, subtract 1/5 = 3/15.
(2/3)|2 -x| = 4/15 - 3/15
(2/3)|2 -x| = 1/15 . . . . . . . . matches the first choice
Now, multiply by 3/2.
|2 -x| = 3/30
|2 -x| = 1/10 . . . . . . . . . . . . matches the third choice
___
If you decide to distribute the coefficient 2/3 instead, you have
1/5 + |2·2/3 -x·2/3| = 4/15
1/5 + |4/3 -2/3x| = 4/15 . . . . matches the selected choice
Answer:
The desired equation is y = (-8/3)x + 26/3.
Step-by-step explanation:
Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.
Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:
y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b
Multiply all terms by 3 to clear out the fraction:
-6 = -32 + 3b.
Then 26 = 3b, and b = 26/3.
The desired equation is y = (-8/3)x + 26/3.