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Ierofanga [76]
3 years ago
9

Solve the following quadratic equation for all values of xx in simplest form. 17-2x^2=-21

Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

17-2x^2=-21

Step-by-step explanation:

17-1x=-21

17-21=x

-4=x/x=-4

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This is a function<br><br> Question 4 options:<br> True<br> False
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False
-3 is not greater than positive 3


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3 years ago
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If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)), then the range of G is
lana66690 [7]

Answer:

\{0, 2, 6, 7\}

Step-by-step explanation:

You are given the relation G = \{(-1, 7),(-8, 2),(0, 0),(6, 6)\}

This means that

f(-1)=7\\ f(-8)=0\\f(0)=0\\f(6)=6

The input values of this relation are -1,\ -8,\ 0,\ 6, so the domain of this relation is \{-8,-1,0,6\}

The output values of this relation are 7,\ 2,\ 0,\ 6, so the range of this relation is \{0, 2, 6, 7\}

8 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
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Step-by-step explanation:

step one Distribute

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step two Subtract the numbers

x−45=16x+24−18

x−45=16x+24−18

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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