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DanielleElmas [232]
3 years ago
5

Hallar el menor número no divisible por 4, 6, 9, 11 y 12, tal que al dividirlo por estos números se obtengan restos iguales.

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

397

Step-by-step explanation:

Sea 'p (x)' el número que no es divisible por 4, 6, 9, 11 y 12 de manera que cuando se divide por estos números da un resto igual, tenemos;

Por teorema del resto, tenemos;

p (x) = (x - a) · Q (x) + R

Dónde;

p (x) = El número, que se divide

Q (x) = El cociente

(x - a) = El divisor

R = El resto

Dado que el número más pequeño es 4, el resto, 0 <R <4

Para el número entero más pequeño arriba (x - a) · Q (x), tenemos;

R = 1

Observamos que el mínimo común múltiplo de 4, 6, 9, 11 y 12 = 396, por lo tanto, podemos tener;

(x - a) · Q (x) = 396

R = 1, dar;

p (x) = 396 + 1 = 397

Por lo tanto;

El número que no es divisible por 4, 6, 9, 11 y 12, de manera que cuando se divide por estos números da residuos iguales, p (x) = 397

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