Pls help due today need ASAP

Please help please help please helppppppppppppppppppp

Amiraneli [1.4K]

Answer:

600

Step-by-step explanation:

3 0

3 years ago

Please help need to be in on monday 22 may and im struggling

slavikrds [6]

1 = 84
2 = 40
3 = 54
4 = 18
5 = 35
6 = 21
7 = 33
8 = 26
9 = 30
10 = 8
11 = 27
12= 28
13 = 21
14 = 13
15 = 10

( Task 2 ) Hope this helps :)

5 0

3 years ago

Read 2 more answers

11) V = tr2h solve for r2

Trava [24]

Answer:

$r^{2}=\frac{V}{\pi h}$

Step-by-step explanation:

To solve an equation for one of its variables do that:

Underline the variable
Separate it one side and the other terms on the other side
Make its coefficient equal to 1

Let us use these steps to solve our question

∵ V = πr²h

→ Underline r²

∴ V = π<u>r²</u>h

→ Take π and h to the other side by dividing both sides by πh

∵ $\frac{V}{\pi h}=\frac{\pi r^{2}h}{\pi h}$

∴ $\frac{V}{\pi h}=r^{2}$

→ The coefficient of r² is 1, so switch the two sides

∴ $r^{2}=\frac{V}{\pi h}$

8 0

4 years ago

There are 1200 students at Sophie’s school. One student’s name will be drawn at random to win a new bike. Hannah and Ethan are S

fomenos

Hi Mackenzie.

Given that we have a probability question with the term "or", we are going to be adding individual probabilities.
We have Ethan, Hannah, and Sophie all included with the drawing.
This means we need to add each of their individual probabilities, 1/1200, together.

1/1200 + 1/1200 + 1/1200 = 3/1200;
To simplify: 1/400

Your answer is:
The probability of Ethan, Hannah, or Sophie being drawn is 1/400.

I hope this helps!

5 0

3 years ago

Hello, help me please))

Fed [463]

Answer:

6
9
1/8
-10/11

Step-by-step explanation:

You can rewrite the given log expressions to express them in terms of ln(a), ln(b), and ln(c). Then substituting the given values will produce the value of the expression.

Or, you can define the variables 'a', 'b', and 'c' and let your calculator compute these directly.

__

$\ln\left(\dfrac{a^4}{b^4c^{-2}}\right)=4\ln(a)-(4\ln(b)-2\ln(c))=4\cdot2-4\cdot3+2\cdot5=\boxed{6}$

$\ln\left(\sqrt{b^{-2}c^4a^2}\right)=\dfrac{1}{2}\left(-2\ln(b)+4\ln(c)+2\ln(a)\right)=\ln(a)-\ln(b)+2\ln(c)\\\\=2-3+2\cdot5=\boxed{9}$

$\dfrac{\ln(a^1b^2)}{\ln(bc)^2}=\dfrac{\ln(a)+2\ln(b)}{(\ln(b)+\ln(c))^2}=\dfrac{2+2\cdot3}{(3+5)^2}=\dfrac{8}{64}=\boxed{\dfrac{1}{8}}$

$\ln(c^{-2})\left(\ln\dfrac{a}{b^{-3}}\right)^{-1}=\dfrac{-2\ln(c)}{\ln(a)-(-3)\ln(b)}=\dfrac{-2(5)}{2+3\cdot3}=\boxed{-\dfrac{10}{11}}$

_____

The applicable rules of logarithms are ...

ln(ab) = ln(a) +ln(b)
ln(a/b) = ln(a) -ln(b)
ln(a^b) = b·ln(a)
ln(a) = b ⇔ a = e^b

Of course, a square root is the same as a 1/2 power.

7 0

2 years ago